Question

Construction a quad ABCD.AB=7.2cm,BC=6.5cm,CD=5.9,AD=6.1 and AC=8.4cm​

Answer 1

Answer:

Given. ABCD is a quadrilateral.

AB = 6 cm, BC = 6 cm, ∠BAC = 50°, ∠ACD = 30° and ∠CAD = 100°

Formula used. Area of triangle =

× Base × Height

Steps for construction.

Step 1 : Draw a line AB of 6cm

Step 2 : Draw an angle of 50° on point A and extend ray AC’

Step 3 : Make an arc of 6cm from point B and intersect it on AC’

Mark intersection point of arc and ray AC’ as point C

Step 4 : Draw an angle of 30° on point C on AC and extend

ray to CD’

Step 5 : Make an angle of 100° on point A on AC and extend ray to

intersect ray CD’ mark the intersection point as D

Step 6 : Join BD

Step 6 : Draw perpendicular from A and C on BD and name the intersecting point as E and F respectively

Area of quadrilateral = Area of ΔACB + Area of ΔACD

=

× AE × BD +

× CF × BD

=

× BD × (AE + CF)

=

× 10.5cm × (1.4cm + 5.5cm)

= 36.225cm2

Conclusion. Hence quadrilateral ABCD is constructed and its Area is

36.225cm2

Answer 2

Step-by-step explanation:

this answer satisfies above