construction a rhombus whose diagonals are 8cm6cm
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Steps of Construction:
(i) Draw BC = 6 cm. (ii) Draw AD = 8 on perpendicular to BC. ... (v) Draw perpendicular bisectors of AB, and CD, which meet at 0. (vi) Since AD and BC are diagonals of rhombus and meet at 0.
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Answer:
Construct a rhombus ABCD in which diagonal AC = 8 cm and diagonal BD = 6.2 cm.
Draw line segment AC = 8 cm.
Draw the perpendicular bisector of AC.
With O as the centre and radius =3.1 cm, mark arcs on both the sides of AC to intersect its perpendicular bisector. Mark the points of intersection as B and D.
Join points A, D, points C, D, points C, B, and points B, A.Construct a rhombus ABCD in which diagonal AC = 8 cm and diagonal BD = 6.2 cm.
Draw line segment AC = 8 cm.
Draw the perpendicular bisector of AC.
With O as the centre and radius =3.1 cm, mark arcs on both the sides of AC to intersect its perpendicular bisector. Mark the points of intersection as B and D.
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