Question

construction a triangle ABC with sides BC=6 cm ,AB=5 cm and AC=7 cm . Then construct another triangle whose sides are 3/4 of the corresponding sides of the triangle ABC.​

Answer 1

$\huge \mathcal{ \fcolorbox{cyan}{black}{ \green{Solution:-}}}$

Step 1 : 

Draw a line BC  = 6 cm and take radius of 5 cm and center " B "  draw an arc and with radius of 7 cm and center " C "  draw an arc that intersect our previous arc at  " A "  .

Step 2 :

Join AB and AC , we get triangle ABC

Now We construct another triangle with scale factor 35 , As :

              

Step 1 :

Below BC,  draw a line BX  As  ∠ CBX is any acute angle and draw three arcs of equal radii on line BX that intersect at X1 . X2 , X3 , X4 and  X4 AS :

  BX1  = X1 X2 = X2 X3 = X3 X4 = X4 X5

Step 2 :

Join X5 to C and than draw a line from X3  as parallel to X5C that intersect our line BC at C' .

Step 3 :

Draw line from C' as parallel to CA that intersect line AB at A'

We get triangle A'BC' whose sides are 35 of corresponding sides of triangle ABC