Math, asked by muskan773924, 1 year ago

construction a triangle PQR angle Q= 60° angle R= 30° PQ+QR+RP = 12.5 cm

Answers

Answered by ankitachoudhary2
13
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Answered by SushmitaAhluwalia
20

CONSTRUCTION OF ΔPQR WITH ∠Q = 60° AND ∠R = 30° AND

PQ + QR + RP = 12.5

  • Draw a line segment AB = 12.5 cm.
  • Construct angle 60° at point A and angle 30° at point B.
  • Draw angle bisectors to angles A and B.
  • Let these angle bisectors intersect at point P.
  • Draw perpendicular bisector to line segment AP.
  • Let this bisector meet AB at Q.
  • Draw perpendicular bisector to line segment BP.
  • Let this bisector meet AB at R.
  • Join PQ and PR.
  • PQR is the required triangle.
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