Question

construction an angle ABC= 90 degree locate a point p which is 2.5cm from AB and 3.2cm from BC.​

Answer 1

Step-by-step explanation:

Steps of construction :

Draw ∠ABC = 90°

From AB, cut BD = 3.2 cm.

Through point C, draw CH⊥BC. From CH, cut CE = 3.2. Join DE. Now DE is a line parallel to BC and at a distance of 3.2 cm from BC.

From BC cut BM = 2.5 cm.

Through point A, draw AK ⊥ AB. From AK cut AN = 2.5 cm. Join NM. Therefore NM is parallel to AB and at a distance of 2.5 cm from AB.

DE and MN intersect each other at P. Thus P is the required point which is 2.5 cm from AB and 3.2 cm from BC