construction of a triangle ABC in which AB equal to 4 cm angle a is equal to 60 degree is not possible when the difference of bc and ac equal to
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Answer:
Step-by-step explanation:
In ΔABC, ∠BAC=60° and AB=4 cm. (Given)..... (1)
First of all, we assume that BC=AC ..... (2)
Now we will calculate the lengths of BC or AC to satisfy condition (1).
From the diagram, it is clear that, if CD⊥AB, then D must be the mid point of AB. {As, BC=AC}
Then, AD= DB =2 cm ..... (3)
So, from the right angled ΔADC,
Cos∠CAD= AD/AC
⇒Cos 60°= 2/AC {From (1) and (3)}
⇒1/2= 2/AC
⇒AC=4 cm.
⇒BC=4 cm. {From equation (2)}
Therefore, BC or AC can not be equal
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