Question

construction of triangle

Answer 1

question 5

draw the base BC=6cm and Make angle at B equal to 90°. say XBC

cut the line segment equal to 10cm from the ray BX.

make an angle DCY equal to <BDC

CY intersect BX at A

join ABC we get required triangle

question 6

step1. Draw a line segment, say XY equal to perimeter of triangle 10cm

step2. make an angle LXY equal to  90° and MYX equal to 60°

step3. bisect <LXY <MYX. let these bibectors intersect at point ,say A.

step4. draw a perpendicular bisectors PQ of AX and RS of AY

these PQ  intersect XY at B and RS intersect at  C.

complete the triangle ABC

Question 7

triangle PQR , PQ : QR : PR = 5: 7: 9

perimeter = 8.4cm

PQ = 5/21(8.4) = 2

QR = 7/21(8.4) = 2.8

PR = 9/21(8.4) = 3.6

using these we can draw a triangle