Question

construction step for 110degree angle with the help of protractor​

Answer 1

Draw ∠BXA = 110° with the help of a protractor. Now, we use the following steps for required construction

1.Taking X as centre and any radius daw an arc to Intersect the rays XA and XB, say at E and D, respectively.

2.Taking D and E as centres and with the radius more than 1/2 DE, draw arcs to intersect

each other, say at F.

3.Draw the ray XF.

Thus, ray XF is the required bisector of the angle B X A. On measuring each angle, we get

∠BXC = ∠AXC = 55°.

[∴ ∠BXC = ∠AXC = 1/2 ∠BXA = 1/2 x 110° = 55° ].

Answer 2

Answer:

Draw ∠BXA = 110° with the help of a protractor. Now, we use the following steps for required construction

1.Taking X as centre and any radius daw an arc to Intersect the rays XA and XB, say at E and D, respectively.

2.Taking D and E as centres and with the radius more than 1/2 DE, draw arcs to intersect

each other, say at F.

3.Draw the ray XF.

Thus, ray XF is the required bisector of the angle B X A. On measuring each angle, we get

∠BXC = ∠AXC = 55°.

[∴ ∠BXC = ∠AXC = 1/2 ∠BXA = 1/2 x 110° = 55° ].

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