construction triangle in which BC =30° angle B= 8 cm and AB+AC =12 cm .
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Hey mate
Here is ur answer
Step of construction :
1. Draw BC =8 cm
2. Construct angle CBX =30°
3. Along BX cut BD =12 cm .
4. Join CD
5. Draw PQ perpendicular bisector of CD .
6. PQ intersects BD at A and is perpendicular bisector of CD .
7. Join CA; CA = AD because AL is perpendicular bisector of CD
Hence , triangle ABC is the required triangle.
thank you.
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