Container A = 100 g of 109% oleum Container B = 100 g of 118% oleum Ratio of % of free SO, in container A and B
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Given:
mass of Container A=100 g
percentage=109%
mass of Container B=100 g
percentage in B=118%
To Find:
Ratio of % free SO, in container A and B
Solution:
For A
100 g of 109% is
mass of SO in A
For B
100 g of 118% is
mass of SO in B is
The ratio of A and B is
Hence, the ratio of A and B is 0.5.
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