Chemistry, asked by swarnim175, 9 months ago

Container I and II contain H,SO, and oleum respectively.
H,SO
100 g in
1 L solution
Oleum
100 g in
1 L solution
Container-1
Container-11
If 0.1 M NaOH is added in Container-I then it required x L NaOH for complete neutralisation
while Container-ll required 1.09x L NaOH for complete neutralisation. The tap in container
Il is now opened and oleum mixture is allowed to drip from Container-11 at 2 g/s then the
minimum time (in s) to the nearest integer after which container-II will require x L of NaOH
for complete neutralisation is (Density of solution of container II is 1.4 g/mL]​

Answers

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1

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