Math, asked by lk3295717, 1 day ago

contains 21 28 litre of pure milk 3 litres of milk is replaced by equal quantity of water this process is repeated 2 times more find the remaining quantity of milk at the end of the process
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Answers

Answered by kavitahari04
0

Answer:

contains 21 28 litre of pure milk 3 litres of milk is replaced by equal quantity of water this process is and we have to find here milk process so divide all numbers okay

Answered by 44PurpleOcean
0

Answer:

Container contains 40 litres, initially 4 litre milk taken out from that. After that remaining quantity of milk is

40–4=36 litres

Now the container is filled with water . Total quantity is 40 litres out of 40 only 36 litres is milk. If another 4 litres is taken out from the container it is not fully milk. So we have to find quantity if milk

36/40*4=3.6 litres

In 4 litres only 3.6 is milk, now we deduct this also from the total milk quantity

36–3.6=32.4litres

Once again the process is repeated

32.4/40*4=3.24litres

Now deduct this from 32.4litres

32.4–3.24=29.16litres.

Container contains 29.16litres of milk.

29.16 liters (Option B)

If you are taking out 4 liters out of a 40 liter solution and replacing it with water, you are effectively replacing 1/10th of the solution with water.

=> Fraction of milk will become (9/10) of the original

If the process is repeated 'n' times, fraction of milk will become (9/10)^n of the original.

We are given the process was done thrice

=> Final quantity of milk = (9/10)^3 * 40 = 0.729*40 = 29.16

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