Question

content in the soil, with specific gravity of soil particles 2.75. The weight of soil and remaining water filled in pycnometer without air bubbles was 1415 g and the weight of pycnometer filled with water alone was 1275 g. The moisture content in the soil is​ ?

Ans:
WATER CONTENT = ([{(W2 - W1)/(W3 - W4)}{(G-1)/G]-1)*100.

Where,

W1 = wt. of empty Pycnometer = 400 g.

W2 = wt. of the Pycnometer with wet soil = 260 + 400 = 660.

W3 = wt. of the Pycnometer and soil, filled with water = 1415.

W4 = wt. of Pycnometer filled with water only = 1275.

G = Specific gravity of solids = 2.75.

Water content = ([(660 - 400)/(1415 - 1275)][(2.75 - 1)/(2.75)] - 1)*100.

= [(260/140)(1.75/2.75) - 1]*100 = 18.18% answer

Answer 1

this is very tough question

Explanation:

I I didn't understood this question, it is very long