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How many elements can be accommodated in the present set up of the long form of the periodic table ? Explain .

Answer 1

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To know about this First we should know about What is Aufbau Principle .

AUFBAU PRINCIPLE :- Orbitals are filled in order of their increasing energy. The order of energy and hence that of filling of orbitals is found by ( n+l ) rule. It states " lower the ( n+l ) value, lower is the energy. If two orbitals have same ( n+l ) value, orbital with lower value of n has lower energy."

Thus , the order is :

1s < 2s < 2p < 3s < 3p < 4s < 3d < 4p < 5s < 4d < 5p < 6s < 4f < 5d

( n+l ) = 1 2 3 3 4 4 5 5 5 6 6 6 7 7

Now ,

➡ According to the present set up of the periodic table , there are seven periods ( principal quantum number , n = 7 ) and four blocks ( s, p, d- and f- block elements ) . So the maximum number of elements are accommodated in the present set up of the periodic table with the accordance of the Aufbau Principle is :-

1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 4d^10 5p^6 6s^2 4f^14 5d^10 6p^6 7s^2 5f^14 6d^10 7p^6 = 118 .

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