Question

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permutations and combination s​

Answer 1

9 ARE TO BE ON 1 SIDE.4 ARE ALREADY ON ONE SIDE AND 3 ON OTHER SIDE.

THERE ARE 11 LEFT.

WE CAN SELECT 5 OF THEM IN 11C5 WAYS TO SIT ALONG WITH 4.

REST WILL AUTOMATICALLY GO TO OTHER SIDE.THIS CAN BE DONE IN ONLY 1 WAY .

NOW 9 ON EITHER SIDE CAN BE ARRANGED IN 9! WAYS...SO THE TOTAL NUMBER OF ARRANGEMENTS ARE

11C5*9!*9!

Answer 2

HEY WELCOME TO MY PERFECT ANSWER:-)

●Permutations & Combinations

Since, 4 + 3 guests have already selected the sides where they will be seated.

Out of remaining 11 guest ,we have to select 5 for one side, and the remaining will sit on the other side.

We can choose 5 guest for a particular side in 11C5 ways

Now 9 guests in the particular side can be arranged in 9! ways and 9 on the other side in 9! ways as well.

Hence the total number of ways

=11C5. (9!)^2

Basic Definition➫

Permutations-Permutation is arrangement of values in all possible ways.The word arrangement is used to emphasize that the order of the things is important.

Combination➫Combination means selection of things. The word selection is used, when the order of things has no importance.

Basic Formulae✌✌see attachment