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How can chlorine have an oxidation number 3 in chlorite?
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1
yeah sure for your help
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This is because cholrine is able to engage its d- orbital by hybridization, which an electron in a lower engery level of may be an s- orbital or any other orbital below the d- orbital , reaches an exited state where it is promoted to a higher energy level which is d- orbital . The D - orbital has an orbital orientation of 5. l
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------------- Here is your answer -------------
This is because cholrine is able to engage its d- orbital by hybridization, which an electron in a lower engery level of may be an s- orbital or any other orbital below the d- orbital , reaches an exited state where it is promoted to a higher energy level which is d- orbital . The D - orbital has an orbital orientation of 5. l
:: : : : : : : : : : : : : : : : : :
hope you satisfied with my answer
please mark as brainlest as if it helps you
FuturePoet:
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Answered by
3
heyy dear ur answer ......
According to electronic configuration of chlorine...(17)
1s2 2s2 2p6 3s2 3p5
According to electronic configuration of chlorine...(17)
1s2 2s2 2p6 3s2 3p5
Oxydation state = unpaired electrons which can be paired by accepting stranger electrons(from other elements) or being gived to other elements.
When accepting electrons = Ox state decrease ; When giving electrons = Ox state increase
So :
3s2 3p5 3d0 :
[||] [||][||][|] [][][][][] = 1 unpaired electron = Ox state +1 and -1 (hypochlorites and chlorides)
3s2 3p4 3d1 :
[||] [||][|][|] [|][][][][] = 3 unpaired electrons = Ox state +3 (chlorites).....
......i hope it will help u..............@kundan
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