Question

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Answer 1

Answer:In this type of question, you need to remember the symmetry of a parabola.

Always use the x axis for calculation of distance as it doesn't involve gravity.

Now, let the distance on x axis in t1 be x and the distance on x axis in time t2 be y.

FROM SYMMETRY OF PARABOLA

x +y = R , where R is the range of the parabola.

Individually calculate x and y and add them to get range (which is already known by formula).

check out the attached photo.

THE ANSWER IS 40 m/sec.

Please check the answer in the assignment book

Sorry for Bad handwriting !!

Explanation:

Answer 2

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Explanation:

TO FIND;

Initial velocity of particle[U]=?

GIVEN;

Final velocity [V]=0

Value of g=10m/s

t1=1sec

t2=3sec

So from equation of motion we know that,

V=U+at

substituting the value given we get;

v=u+at

0=u+(-g)*t2-t1

let us assume the value of acceleration of particle=g

we know that g acts downward so we get value of a=-g=-10m/s

0=u+(-10)3-1

0=u-10*2

-u= -20

u=20

Thus we get the initial velocity of particle as 20 m/s