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12. P(x)=2x3+9x2+x+k
X=2*1+9*1+1+k
=2*9+1×k
=12+k
K=-12
13. P(x)= 2x3-3x2-18x+a
X=4
=2*(4)3-3*(4)2-18*4+a
=8+a
a = -8
X=2*1+9*1+1+k
=2*9+1×k
=12+k
K=-12
13. P(x)= 2x3-3x2-18x+a
X=4
=2*(4)3-3*(4)2-18*4+a
=8+a
a = -8
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Answered by
5
Hello Dear!!!
Here's your answer...
12)
2x^3 + 9x^2 +x + k =0
x -1 is factor
zero of x-1 is
x-1=0
x=1
substitute
2x^3 + 9x^2 +x + k =0
2(1)^3 + 9(1)^2 + 1+k =0
2+9+1+k=0
k = -12
______________________
13)
2x^3 - 3x^2 -18x+a
zero of x-4 is
x-4=0
x=4
substitute
2x^3 - 3x^2 -18x+a = 0
2(4)^3 - 3(4)^2 - 18(4) + a =0
2(64) - 3(16) - 72 + a = 0
128 - 48 - 72 + a = 0
8 +a=0
a = -8
__________________________
14)
ax^3 - x^2-2x+4a-9
zero of x+1 is
x+1=0
x=-1
substitute
ax^3 - x^2-2x+4a-9=0
a(-1)^3 - (-1)^2 -2(-1) + 4a -9 =0
-3a -1 +2 +4a -9 =0
a-8=0
a = 8
_________________________
Here's your answer...
12)
2x^3 + 9x^2 +x + k =0
x -1 is factor
zero of x-1 is
x-1=0
x=1
substitute
2x^3 + 9x^2 +x + k =0
2(1)^3 + 9(1)^2 + 1+k =0
2+9+1+k=0
k = -12
______________________
13)
2x^3 - 3x^2 -18x+a
zero of x-4 is
x-4=0
x=4
substitute
2x^3 - 3x^2 -18x+a = 0
2(4)^3 - 3(4)^2 - 18(4) + a =0
2(64) - 3(16) - 72 + a = 0
128 - 48 - 72 + a = 0
8 +a=0
a = -8
__________________________
14)
ax^3 - x^2-2x+4a-9
zero of x+1 is
x+1=0
x=-1
substitute
ax^3 - x^2-2x+4a-9=0
a(-1)^3 - (-1)^2 -2(-1) + 4a -9 =0
-3a -1 +2 +4a -9 =0
a-8=0
a = 8
_________________________
ur wlcm Ma'm
amazing answer! ☺.
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