Question

CONTENT QUALITY REQUIRED ⬇️⬇️⬇️⬇️⬇️⬇️

See the questions in the attachment.

Answer 1

Hello friends!!

Here is your answer :

Ans 6.

$p(x) = 2 {x}^{3} - 9 {x}^{2} + x + 15 \: \: \: and \: \: \: g(x) = 2x - 3$


Here,
$zero \: \: of \: \: g(x) \: \: is \: \: \frac{3}{2}$


When we divide p(x) by g(x) using remainder theorem, we get the remainder p(3/2)


$p( \frac{3}{2} ) = 2 {( \frac{3}{2}) }^{3} - 9 {( \frac{3}{2} ) }^{2} + \frac{3}{2} + 15$


$= 2 \times \frac{27}{8} - 9 \times \frac{9}{4} + \frac{3}{2} + 15$


$= 1 \times \frac{27}{4} - \frac{81}{4} + \frac{3}{2} + 15$


$= \frac{27}{4} - \frac{81}{4} + \frac{3}{2} + 15$


$= \frac{27 - 81 + 6 + 60}{4}$


$= \frac{93 - 81}{4}$


$= \frac{12}{4}$


$= 3$


Hence, remainder is 3.

______________________


Ans 7.

$p(x) = {x}^{3} - 2 {x}^{2} - 8x - 1 \: \: \: and \: \: \: g(x) = x + 1$


Here,

$zero \: \: of \: \: g(x) = - 1$

When we divide p(x) by g(x) using remainder theorem, we get the remainder p(-1).


$p( - 1) = {( - 1)}^{3} - 2 {( - 1)}^{2} - 8( -1 ) - 1$


$= - 1 - 2 \times 1 + 8 - 1$


$= - 1 - 2 + 8 - 1$


$= 8 - 4$


$= 4$


Hence,
Remainder is 4.


Hope it helps you.. ☺️☺️☺️☺️

# Be Brainly

Answer 2

l hope it will be helpful to you :)