Question

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Sum of the n terms of a parallel range is 3n²-n, then find the first term and the commoner

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Answer 1

!! Hey Mate !!

your answer is --

Given,

Sn = 3n^2-n

Now,

S1 = 3×1^2-1 = 3-1 = 2

So, first term is 2

Now,

S2 = 3×2^2 -2 = 12-2 = 10

S2 - S1 = 10-2 = 8

So, second term is 8

Now, common difference is

8 - 2 = 6

Hence, first term is 2 and common difference is 6.

【 Hope it helps you 】