Question

*CONTENT QUALITY REQUIRED*

What is the perimeter of this shape if each rectangle has a perimeter of 222

Answer 1

Given that the perimeter of the shape of the rectangle is 222.

We know that perimeter of a rectangle = 2(l + h)
  
                                     2(l + h) = 222

                                      l + h = 111.     ---------- (1)


Now,

From the figure we can see that:

the top shape consists of 2 height and 1 length.

the bottom shape consists of 2 heights and 2 lengths.

the remaining shapes consist of 2 heights and 2 lengths.

Overall it is 6height + 6length

                   = 6(l + h)

                    = 6(111)

                    = 666.


Hope this helps!

Answer 2

Answer:

666

Step-by-step explanation:

Given that

perimeter of rectangle=222

by removing the over lapping segments we get it as the above photo

then

we can see

total heights=6

total lengths=6

that means 3 triangles

there fore 3 (222)

=666

hope it helps......