Question

★ CONTENT QUALITY SUPPORT REQUIRED ★

★ STANDARD QUESTION 7 ★

The answer with highest efficiency will get marked THE Brainliest , And will be offered an special invitation card

Question is -
If -
$a + 1 = b + 2 = c + 3 = d + 4 = e + 5 = a + b + c + d + e + 3$

Then evaluate -

${a}^{2} + {b}^{2} + {c}^{2} + {d}^{2} + {e}^{2}$

This question needs a perfect answer ; and it doesn't support lazy ones ! Take care

Answer 1

given ,a + 1 = b + 2 = c + 3 = d + 4 = e + 5 = a + b + c + d + e +3

for value a
b=a-1
c=a-2
d=a-3
e=a-4
from eqn a+1=a+b+c+d+e+3
a+1=a+a-1+a-2+a-3+a-4+3
a-5a=-1-1-2-3-4+3
-4a=-8. =>. a=2
therefore
a=2
b=1
c=0
d=-1
e=-2

{a}^{2} + {b}^{2} + {c}^{2} + {d}^{2} + {e}^{2} =
{2}^{2} + {1}^{2} + {0}^{2} + {-1}^{2} + {-2}^{2} =
4+1+0+1+4=10

therefore the ans is 10