Question

continuation
(iv) If the relative molecular mass of Ethane is 30, what is the mass of ethane burned in the above reaction.​

Answer 1

1.Number of moles of CO2

÷4=number of moles of ethane÷2

Number of moles of CO2 =2

2.volume occupied by CO2 in

1=2×22.4=44.8liters

3. volume of oxygen ÷49.6=number of

moles of ethane in 1÷2

Volume of oxygen =24.8 liters.

4. 1=mass÷molecular mass

Mass=1×30=30g

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Answer 2

Answer:

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Explanation:

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