Question

Continuing with the situation, if the force F=80N is directed vertically as shown, the acceleration of the 10Kg block will be? ​

Answer 1

Answer:

rom FBD of 10 kg block,

F=30N,f=0.1×10×10=10N (Assuming kinetic friction coefficient =0.1)

As F>f , so the 10 kg block will move with acceleration a.

Thus, 10a=F−f=30−10=20⇒a=2m/s

2

Answer 2

Answer:

From FBD of 10 kg block,

F=30N,f=0.1×10×10=10N (Assuming kinetic friction coefficient =0.1)

As F>f , so the 10 kg block will move with acceleration a.

Thus, 10a=F−f=30−10=20⇒a=2m/s

2