Continuing with the situation, if the force F=80N is directed vertically as shown, the acceleration of the 10Kg block will be?
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rom FBD of 10 kg block,
F=30N,f=0.1×10×10=10N (Assuming kinetic friction coefficient =0.1)
As F>f , so the 10 kg block will move with acceleration a.
Thus, 10a=F−f=30−10=20⇒a=2m/s
2
Answered by
5
Answer:
From FBD of 10 kg block,
F=30N,f=0.1×10×10=10N (Assuming kinetic friction coefficient =0.1)
As F>f , so the 10 kg block will move with acceleration a.
Thus, 10a=F−f=30−10=20⇒a=2m/s
2
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