Contract a parallelogram ABCD in which AB=6cm ,AD=4 CM and angle= 40
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Answer:
Draw AB = 6 cm.
Draw ∠PAB = 45°.
Cut AD = 4.8 cm.
From D, draw an arc of radius 6 cm.
From B, draw an arc of radius 4.8 cm which meets first arc at C.
Join BC, CD, AD.
Thus ABCD is the required ||gm.
Draw perpendicular bisector XY of AD which cuts AD at P.
Join AC and BD which intersect at O.
Join OP and measure it.
OP = 3 cm.
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