Question

contract a parallelogram PQRS such that PQ=6.3cm,PR=6.4cm and QS=8.3cm.​

Answer 1

Answer:

Steps to construct a parallelogram:

*Step 1- Draw line QS of length 8.2 cm.

*Step 2- Divide the line segment QS into half i.e 4.1 cm and mark that point as O. Now by taking O as center cut an arc on both the sides of O with a radius of 3.4cm each. And mark that points as P and R.

*Step 3- cut an arc by taking Q as a center and radius QR = 5.2cm to intersect with point R.

*Step 4- cut an arc by taking Q as a center and radius QP = 5.2cm to intersect with point P.

*Step 5- Join sides PQ, PS, QR and RS.

Answer 2

Step-by-step explanation:

Step 1- Draw line QS of length 8.3 cm.

Step 2- Divide the line segment QS into half i.e approx 4.1 cm and mark that point as O. Now by taking O as center cut an arc on both the sides of O with a radius of 3.2cm each. And mark that points as P and R.

Step 3- cut an arc by taking Q as a center and radius QR = 6.3cm to intersect with point R.

Step 4- cut an arc by taking Q as a center and radius QP = 6.3cm to intersect with point P.

Step 5- Join sides PQ, PS, QR and RS.