Contract a triangle ABC with measure AB=5cm,BC=4.2cm,AC=6.5.measure the angles. Write relationship between sides and angles
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i dont know the relation
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According the question we have to construct a Δ ABC .
where AB=5cm,
BC=4.2cm,
AC=6.5.
And also measure the angles.
Let,s start :-
- First we draw a line which is sufficiently prolonged the usage of ruler.
- In this step we will draw points 'B' and 'C' on it such that BC = 4.2cm
- Taking 'B' as Center and radius 5cm , we will draw an arc.
- Here we will consider 'C' as Center and radius 6.5cm , and will draw arc reducing the previous arc at 'A'
- This is the last step, will join BA and CA.
∴ ABC is the required triangle.
"Angle opposite to greater side is more than the angle opposite lesser side" . and measures of angles are :-
∠A = 88° ,
∠C = 48° ,
∠B = 44°.
Ans :- "Angle opposite to greater side is more than the angle opposite lesser side" . ∠A = 88° , ∠C = 48° ,∠B = 44°.
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