Conustruct a triangle abc,bc=4.7angleb= 45°,ab-ac=2cm
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1) draw the base BC and at point b Make an angle,given of 45°
2) cut a line segment BD equal to AB -AC of 2 cm
3) then join DC
4) then draw perpendicular bisector PQ of DC
5) it intersect BD at A. Join AC.
Here ∆ABC is your required triangle
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