Question

conversation telephone follow ED F(x) = (e^-x/2)/s where x>0Find probablity density ? ​

Answer 1

1/e is the answer

solutions is attached above ......

Answer 2

Answer:

Given:

Conversation telephone follow ED F(x) = (e^-x/2)/s where x > 0.

Find:

Find probablity density.

Calculations:

P => The conversation will be exceed s min.

$\huge\red{ = > P ( x > 5 )} \\ \huge\red{ = > \infty \: \huge\gamma \:_{5} \frac{1}{5} e { - x}^{5}} \\ \huge\red{ = > \binom{e - \frac{x}{5} } { \frac{ - x}{5} } _{5}{}^{ \infty } } \\ \huge\red{= > \frac{1}{e}}$