Converse of Pythagoras therom proof
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- A Proof for the Converse of the Pythagorean Theorem. Converse of the Pythagorean Theorem: If the square of the length of the longest side of a triangle is equal to the sum of the squares of the lengths of the other two sides, then the triangle is a right triangle.
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Converse of Pythagoras Theorem.
Statement:
In a triangle, if square of one side is equal to the sum of the squares of the other two sides, then the angle opposite the first side is a right angle.
Proof:
Here, we are given a triangle ABC in which AC²= AB² + BC²
We need to prove that ∠B = 90°
To start with, we construct a ΔPQR right-angled at Q such that PQ = AB and QR = BC.
Now, from Δ PQR, we have:
PR² = PQ² + QR² (Pythagoras Theorem, as ∠Q=90°)
or PR² = AB² + BC² (By construction)........ (1)
But AC² =AB² + BC² (Given).......... (2)
So, AC=PR (From (1) and (2)).............. (3)
Now, in ΔABC and ΔPQR,
AB=PQ (By construction)
BC=QR (By construction)
AC=PR (Proved in (3))
So, ΔABC≃ΔPQR (By SSS congruence)
∠B=∠Q (Corresponding angles of congruent triangles)
∠Q=90° (By construction)
So ∠B=90°
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