converse of thales theorem
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take a triangle ABC .given
construction draw a line DF
proof; to prove that DE//BC
let us take DE is not parllel to BC and DF//BC
by thales therom AD/DB=AF/FC
from this we get F=E
But ED IS NOT PARALLEL to BC
therefore DE//BC
construction draw a line DF
proof; to prove that DE//BC
let us take DE is not parllel to BC and DF//BC
by thales therom AD/DB=AF/FC
from this we get F=E
But ED IS NOT PARALLEL to BC
therefore DE//BC
Answered by
0
Answer:
If a line divides any two sides of a triangle in the same ratio, then the line must be parallel to the third side.
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