conversion of isopropylbromide to isoprppylisocyanide
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Explanation:
N-propyl bromide reacts with alkaline KOH undergoes dehydro halogination to form propene.
CH3CH2CH2-Br + alc.KOH → CH3CH=CH2
propene reacts with HBr in the presence of peroxide to form isopropyl bromide. this ANTI MARKOWNIKOFFS addition
CH3CH=CH2 + HBr + peroxide → CH3CH2BrCH3
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