Conversion of methoxymethane to Iodomethane
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The mechanism of the reaction of HI with methoxymethane involves the following steps:
When HI is in excess and the reaction is carried out at a high temperature, the methanol formed in the second step reacts with another HI molecule and gets converted to methyl iodide
When HI is in excess and the reaction is carried out at a high temperature, the methanol formed in the second step reacts with another HI molecule and gets converted to methyl iodide
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Conversion of methoxymethane to Iodomethane is carried out by excess amount of HI.
Methoxymethane is CH₃OCH₃
Iodomethane is CH₃I
When excess amount of HI (hydroiodic acid) is reacted with CH₃OCH₃, it gives CH₃OH and CH₃I as product. When the products are further treated with HI as it is in excess, they produce CH₃I as main product.
CH₃OCH₃ + HI → CH₃OH + CH₃I
CH₃OH + HI → CH₃I + H₂O
Thus, the conversion of methoxymethane to Iodomethane can be carried out by excess amount of HI.
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