Math, asked by phials123, 9 months ago

Convert 0.62 DBS into MHz. The correct answer will be marked Brainliest.

Answers

Answered by merinla
0

Answer:

It is not possible to convert

dB into MHz because they both are entirely different quantities representing different measurements

Answered by 9392368008damini
0

Answer:

By definition the spectral power density psd is defined by the power p in watt contained in a certain frequency interval df divided by the width of the frequency interval, then psd= p(watt)/df,

The power p can then measured in dBm scale such that p in dBm= 10 log (p/ 1 milliwat),

Then in this case the the psd in units of dbm/ Hz= p in dbm/ df in Hz,

I f you want to express psd in dBm /MHz, it will be equal= p in dbm/ df in MHz,

So, numerically, psd in dbm /Hz= p in dbm/ 30000 Hz,

In case ofpsd in dbm/MHz= p in dbm/ 0.03 MHz

This is the right way to define such quantities and calculate them.

I do not understand why do you define the frequency interval in dB.

The dbm scale is applied for the power only.

Step-by-step explanation:

By definition the spectral power density psd is defined by the power p in watt contained in a certain frequency interval df divided by the width of the frequency interval, then psd= p(watt)/df,

The power p can then measured in dBm scale such that p in dBm= 10 log (p/ 1 milliwat),

Then in this case the the psd in units of dbm/ Hz= p in dbm/ df in Hz,

I f you want to express psd in dBm /MHz, it will be equal= p in dbm/ df in MHz,

So, numerically, psd in dbm /Hz= p in dbm/ 30000 Hz,

In case ofpsd in dbm/MHz= p in dbm/ 0.03 MHz

This is the right way to define such quantities and calculate them.

I do not understand why do you define the frequency interval in dB.

The dbm scale is applied for the power only.

Best wishes

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