Convert 1 dyne into newton using dimensional analysis
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258
the dimensional formula of Force F =
[M 1 L 1 T -2 ]
So a =1, b=1, c=-2
Now because Newton is in m.k.s
system, we have
M 1 = 1kg
L 1 = 1m
T1 = 1s
M 2 = 1g
L 2 = 1cm
T2 = 1s
n 1 = 1 Newton
n 2 = ?
Using the formula
n 2 = n 1 [M 1 /M 2 ]a [L 1/L 2 ]b [T 1/T 2 ]c
n 2 =1 [1kg/1g] 1[1m/1cm] 1 [1s/1s] -2
n 2 =1[1000g/1g] 1[100cm/1cm] 1 x1
n 2 =1000×100 = 100000 = 10 5 dynes
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one dyne into newton it is 10 ^-5 newton
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