CONVERT 1 newton into dyne
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Answered by
5
hello dude/idk---:)
here is ur answer-------
Now because Newton is in m.k.s system,We Have. M1 = 1kg, L1 = 1m, T1 = 1sM2 = 1g, L2 = 1cm, T2 = 1s
n1= 1 Newtonn2 = ?Using the formulan2= n1[M1/M2]a [L1/L2]b [T1/T2]c
n2= 1 [1kg/1g]1 [1m/1cm]1 [1s/1s]-2
n2= 1[1000g/1g]1 [100cm/1cm]1 x1n2= 1000×100 = 100000 = 105 dynes
tysm.@gozmit
here is ur answer-------
Now because Newton is in m.k.s system,We Have. M1 = 1kg, L1 = 1m, T1 = 1sM2 = 1g, L2 = 1cm, T2 = 1s
n1= 1 Newtonn2 = ?Using the formulan2= n1[M1/M2]a [L1/L2]b [T1/T2]c
n2= 1 [1kg/1g]1 [1m/1cm]1 [1s/1s]-2
n2= 1[1000g/1g]1 [100cm/1cm]1 x1n2= 1000×100 = 100000 = 105 dynes
tysm.@gozmit
Answered by
16
heya dear user
here is ur answer
by dimensional analysis
according to Newton in m.k.s system , we have
m1 = 1kg
l1 = 1 m.
t1 = 1s
m2. = 1g
l2 = 1cm
t2 = 1s
n1 = 1 nueter
using formula
n2= [m1 /m2 ) a (l1 / l2 ) b (t1 / t2 ) c
n2 = 1(1kg / 1g ) 1(1m / 1cm ) 1 (1s /1s )
n2= 1( 1000g/ 1g ) 1 ( 100cm /1m ) 1 × 1
n2 = 1000× 100
n2 = 100000
hence 105dynes
hope it helps
here is ur answer
by dimensional analysis
according to Newton in m.k.s system , we have
m1 = 1kg
l1 = 1 m.
t1 = 1s
m2. = 1g
l2 = 1cm
t2 = 1s
n1 = 1 nueter
using formula
n2= [m1 /m2 ) a (l1 / l2 ) b (t1 / t2 ) c
n2 = 1(1kg / 1g ) 1(1m / 1cm ) 1 (1s /1s )
n2= 1( 1000g/ 1g ) 1 ( 100cm /1m ) 1 × 1
n2 = 1000× 100
n2 = 100000
hence 105dynes
hope it helps
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