Physics, asked by vishalkumar15062003, 1 month ago

Convert 10 Joule into erg with the help of dimensional analysis.​

Answers

Answered by Anonymous
12

\maltese\:\underline{\textsf{\textbf{AnsWer :}}}\:\maltese

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We know that,

\longrightarrow\:\:\sf 1  \: J = 1 \:  kg. m^2 .s^{-2} \\

\footnotesize \bullet  \:  \underline{\:\rm Dimensions \:  of \: 1 \:  kg. m^2 .s^{-2}  = [M L^2 T^{-2}]} \\

\longrightarrow\:\:\sf n_1u_1 = n_2 u_2 \\

\longrightarrow\:\:\sf n_2  =n_1 \Bigg[\dfrac{u_1}{u_2} \Bigg]\\

\longrightarrow\:\:\sf n_2  =1\Bigg[\dfrac{M_1}{M_2} \Bigg]^{1} \Bigg[\dfrac{L_1}{L_2} \Bigg]^{2}\Bigg[\dfrac{T_1}{T_2} \Bigg]^{ - 2}   \\

\footnotesize \bullet  \:  \underline{\:\rm T_1 = T_2} \\

\longrightarrow\:\:\sf n_2  =1\Bigg[\dfrac{M_1}{M_2} \Bigg]^{1} \Bigg[\dfrac{L_1}{L_2} \Bigg]^{2} \\

\longrightarrow\:\:\sf n_2  =1\Bigg[\dfrac{1 \: kg}{g} \Bigg]^{1} \Bigg[\dfrac{1 \: m}{cm} \Bigg]^{2} \\

\footnotesize \bullet  \:  \underline{\:\rm 1 \: kg = 1000 \: g} \\

\footnotesize \bullet  \:  \underline{\:\rm 1 \: m = 100 \: cm \: } \\

\longrightarrow\:\:\sf n_2  =1\Bigg[\dfrac{1000 \: g}{g} \Bigg]^{1} \Bigg[\dfrac{100 \: cm }{cm} \Bigg]^{2}

\longrightarrow\:\:\sf n_2  =1\Bigg[1000  \Bigg]^{1} \Bigg[100   \Bigg]^{2}

\longrightarrow\:\:\sf n_2  =1\Bigg[1000  \Bigg] \Bigg[100 00  \Bigg]

\longrightarrow\:\:\sf n_2  = {10}^{7}

\longrightarrow\:\: \underline{ \underline{\sf 1  \: J =  {10}^{7}  \: erg}}

\longrightarrow\:\: \underline{ \underline{\sf 1 0 \: J = 10 \times  {10}^{7}  \: erg}}

\longrightarrow\:\: \underline{ \underline{\sf 1 0 \: J =   {10}^{8}  \: erg}}

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Anonymous: Awesome!!
Anonymous: Thanks <33
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