Convert 1N into dynes using dimensional analysis.
Answers
Answered by
8
1N
[Force]=[MLT^ -2]=[mass × velocity / time]
=[kg×m/sec^2]
In CGS units
1 kg =1000g
1 m =100cm
1sec = 1 sec
so N in CGS is 1000×100×1^2 gm/s^2
= 10^5gm/s^2=10^5dyne
HOPE IT HELPS.....
[Force]=[MLT^ -2]=[mass × velocity / time]
=[kg×m/sec^2]
In CGS units
1 kg =1000g
1 m =100cm
1sec = 1 sec
so N in CGS is 1000×100×1^2 gm/s^2
= 10^5gm/s^2=10^5dyne
HOPE IT HELPS.....
Answered by
4
Hey.....
F=[M1L1T-2]
1dyne = gcm/s^2
So here we would be using the trick of going from unknown system to known...
Or in other words convert g,cm to kg and m
So here we have
= 10^-3kg * 10^-2 m/ s^2 ( we will not change sec as it is already in S. I. Units)
10^-5 kgm/s^2
(Kgm/s^2 is force whose unit is Newton )
So 10^-5 Newton
So 1 dyne =10^-5 newton
Hope it helps...!!
F=[M1L1T-2]
1dyne = gcm/s^2
So here we would be using the trick of going from unknown system to known...
Or in other words convert g,cm to kg and m
So here we have
= 10^-3kg * 10^-2 m/ s^2 ( we will not change sec as it is already in S. I. Units)
10^-5 kgm/s^2
(Kgm/s^2 is force whose unit is Newton )
So 10^-5 Newton
So 1 dyne =10^-5 newton
Hope it helps...!!
Similar questions