convert 2-3i/3+4i into a+ib form
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Step-by-step explanation:
2-3i/3+4i
=2-3i/3+4i * 3-4i/3-4i
=(2-3i) *(3-4i) /(3+4i) *(3-4i) [i²=√-1 *√-1= -1
=6-8i-9i+12i²/ 3²-(4i)² [since, (a+b) (a-b)=(a²-b²) ]
=6-12-17i / 9+16
= -6-17i / 25
= -6/25 - 17i/25 – is of the form a+ib.
I HOPE IT HELPS
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