Question

convert 2A.1B from base 16 to base 10​

Answer 1

Answer:

We have :

$\\\tt \fbox{ \center 2 }\ \fbox{A} \ . \ \fbox{1 } \ \fbox{B}$

Now,

since it's a hexadecimal conversion,

$\begin{center}\begin{tabular}{ c c c c }\\ 16^1 & 16^0 & 16^{-1} & 16^{-2} \\ 2 & A & 1 & B\\ 2x16 & 10x16^0 &1x16^-1 &11x16^-2\\32&10&0.0625&0.04296875\end{tabular}\end{center}$

Now,

The final value,

$(2A.1B)_{16} = (32+10+0.0625+0.04296875)_{10} = {42.10546875}_{10}$