Convert 5J of heat in calories.
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Answer:
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Explanation:
Lets do step by step,
5g ice at zero to 5g water at zero,
Q1=m×lf=5×80=400 cal
5g water at 0 to 5g water at 100°C,
Q2=msΔT=5×1×100=500 cal
5g water at 100°C to 5g steam at 100°C,
Q3=mlv=5×540=2700 cal
Q=Q1+Q2+Q3=3600 cal
Option C is the correct answer
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