Convert 63 (the decimal number) into binary number system. Show the process.
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Answer:
111111
Explanation:
Perform the successive MOD operation by 2 for the given decimal number 63 and note down the remainder (either 0 or 1) for each operation. The last remainder is the MSB (most significant bit) and the first remainder is the LSB (least significant bit).
63 / 2 = 31 : Remainder is 1 → LSB
31 / 2 = 15 : Remainder is 1
15 / 2 = 7 : Remainder is 1
7 / 2 = 3 : Remainder is 1
3 / 2 = 1 : Remainder is 1
1 / 2 = 0 : Remainder is 1 → MSB
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