Question

convert (85)10 into binary num using repeated division by 2 method any sum of power 2(5)​

Answer 1

$\texttt{\textsf{\large{\underline{Answer}:}}}$

• The binary equivalent of the given decimal number (85)₁₀ is (1010 101)₂

$\texttt{\textsf{\large{\underline{Solution}:}}}$

Conversion is given as follows:

$\boxed{\begin{array}{c|c|c}\tt2&\tt85&\\ \tt2&\tt42&\tt1\\ \tt2&\tt21&\tt0\\ \tt2&\tt10&\tt1\\ \tt2&\tt5&\tt0\\ \tt2&\tt2&\tt1\\ \tt2&\tt1&\tt0\\ &\tt0&\tt1\end{array}}$

Now, arrange the remainders obtained from bottom to top,

> (85)₁₀ = (1010 101)₂ (Answer)

$\texttt{\textsf{\large{\underline{Steps To Solve}:}}}$

1. Divide the number by 2.
2. Write the quotient and the remainder and again divide the number by 2.
3. Repeat the above two processes until the quotient becomes 0.
4. Now arrange the remainders obtained from bottom to top.
5. Result obtained will be the binary equivalent of the given decimal number.