Convert a torece of 50 dyn into newton
method of dimensional analysis.
by the
Answers
Answered by
3
Explanation:
ANSWER
the dimensional formula of Force F=[M
1
L
1
T
−2
]
So a=1,b=1,c=−2
Now because Newton is in m.k.s system, we have
M
1
=1kg
L
1
=1m
T
1
=1s
M
2
=1g
L
2
=1cm
T
2
=1s
n
1
=1Newton
n
2
=?
Using the formula
n
2
=n
1
[M1/M2]
a
[L1/L2]
b
[T1/T2]
c
n
2
=1[1kg/1g]
1
[1m/1cm]
1
[1s/1s]
−2
n
2
=1[1000g/1g]
1
[100cm/1cm]
1×1
n
2
=1000×100=100000=10
5
dynes
Answered by
1
Answer:
the dimensional formula of Force F=[M
1
L
1
T
−2
]
So a=1,b=1,c=−2
Now because Newton is in m.k.s system, we have
M
1
=1kg
L
1
=1m
T
1
=1s
M
2
=1g
L
2
=1cm
T
2
=1s
n
1
=1Newton
n
2
=?
Using the formula
n
2
=n
1
[M1/M2]
a
[L1/L2]
b
[T1/T2]
c
n
2
=1[1kg/1g]
1
[1m/1cm]
1
[1s/1s]
−2
n
2
=1[1000g/1g]
1
[100cm/1cm]
1×1
n
2
=1000×100=100000=10
5
dynes
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