Question

convert complex numbers into polar form( -√3 +i)​

Answer 1

Step-by-step explanation:

z=−3+0i

putting

−3=rcosθ,0=rsinθ

9+0=r

2

(sin

2

θ+cos

2

θ)

r

2

=9

r=3

rcosθ

rsinθ

=

−3

0

tanθ=0

θ=0

So, ∣z∣=3, argument of z=0

Therefore, polar form of z is

z=r(cosθ+isinθ)

=3(cos0

∘

+isin0

∘

)