Question

convert each of the complex numbers in the polar form Z=-3​

Answer 1

Answer:

−3+0i

putting 

−3=rcosθ,0=rsinθ

9+0=r2(sin2θ+cos2θ)

r2=9

r=3

rcosθrsinθ=−30

tanθ=0

θ=0

So, ∣z∣=3, argument of z=0

Therefore,  polar form of z is 

z=r(cosθ+isinθ)

=3(cos0∘+isin0∘)

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Answer 2

Answer:

-3+0i is that answer of about the question