convert each of the following into an improper fraction 3 3/10
Answers
Answer:
⇝ Given :-
The volume of a cylindrical bucket is 660 cm³.
Height of Bucket = 11 cm.
⇝ To Find :-
Area of Base of Bucket.
⇝ Solution :-
We Know Volume of Cylinder is :
\large{\orange{ \underbrace{ \underline{\bf\pmb{V_{Cylinder} = \pi r^2h}}}}}VCylinder=πr2hVCylinder=πr2h
Where,
r = Base Radius of Cylinder.
h = Height of Cylinder.
We Have :-
Height of Bucket = h = 11 cm.
Volume of Bucket = V = 660 cm³
Let Base Radius of Bucket be = r.
Hence,
★ Using Formula of Volume :
\begin{gathered}:\longmapsto\pi {\text r}^{2} \times 11 = 660 \\ \end{gathered}:⟼πr2×11=660
\begin{gathered}:\longmapsto\pi {\text r}^{2} = \cancel\frac{660}{11} \\ \end{gathered}:⟼πr2=11660
\purple{ \Large :\longmapsto \underline {\boxed{{\pmb{\pi {r}^{2} = 60 \: {cm}^{2} }} }}}:⟼πr2=60cm2πr2=60cm2
Hence,
\large\underline{\pink{\underline{\frak{\pmb{\text Area \: of \: Base =60 \: {cm}^{2} }}}}}AreaofBase=60cm2AreaofBase=60cm2
hope value is good
Answer:
3 3×10+3. 30+3. 33
3------ = ---------- =. -------- =. -----
10. 10. 10. 10