convert given Boolean expression in standard form to canonical form
y = a'b+bc'
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Answer:
y=a'bc + a'bc' + abc'
Explanation:
multiply each product with the (missing variable + complement of that variable)
y=a'b.(c+c') + bc'.(a+a')
y=a'bc + a'bc' + abc' + a'bc'
y=a'bc + a'bc' + abc' [since A+A=A, so a'bc' + a'bc' = a'bc']
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