Question

convert i-1/cosπ/3+isinπ/3 intobpolar form

Answer 1

= i-{1/(cosπ/3)} + isinπ/3
= i - (1/cos60) + isin60
= i - {1/(1/2)} + i(√3/2)
= i+(√3i/2) - 2
= i{1+(√3/2)} - 2

= i (2+√3)/2 - 2

= -2+ i(2+√3)2 -------> in form of x+iy
where,
x = -2
y = (2+√3)/2
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