Question

Convert
Molecular
form
to ionic
form
MnO + PbO2 + HNO3->
HMnO4 + Pb ( NO3)2+H20​

Answer 1

Answer:

2 MnIIO + 5 PbIVO2 + 10 HNO3 → 5 PbII(NO3)2 + 2 HMnVIIO4 + 4 H2O

This is an oxidation-reduction (redox) reaction:

2 MnII - 10 e- → 2 MnVII

(oxidation)

5 PbIV + 10 e- → 5 PbII

(reduction)

MnO is a reducing agent, PbO2 is an oxidizing agent